p^2+8p-87=-8

Solution for p^2+8p-87=-8 equation:

p^2+8p-87=-8

We move all terms to the left:

p^2+8p-87-(-8)=0

We add all the numbers together, and all the variables

p^2+8p-79=0

a = 1; b = 8; c = -79;
Δ = b2-4ac
Δ = 82-4·1·(-79)
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{95}}{2*1}=\frac{-8-2\sqrt{95}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{95}}{2*1}=\frac{-8+2\sqrt{95}}{2}
$